View Full Version : oCMenu.menuplacement= in %
Hi Thomas,
i have a problem with
oCMenu.menuplacement= %
when i take % / it make the half window
with the menu
approximately by 150 % is the Menu on the
window end.?
bye Ludwig
I don't think I understand... Coudl you elaborate a little?
function Mike(name, mail) {
*****this.name = "Xanth";
*****this.mail = [url:txsv7qxeuh]belgedin@earthlink.net[/url:txsv7qxeuh];
*****return this;
}
Hi Xanth,
is simple ???
oCMenu.menuplacement=new Array('1%','12%','24%','40%','56%','70%','84%','15 0%')
now go`s the menu over the hole site
and here go' s the menu only over 2/3 of the site
oCMenu.menuplacement=new Array('1%','12%','24%','40%','56%','70%','84%','94 %')
is row's
why???
okay?
Your right. There's a bug that makes the percentage function check against the height when it's in rows and width when it's not. Which is obviosly wrong.
I will add a fix for this later today.
-Thomas Brattli-
http://www.bratta.com/
http://www.dhtmlcentral.com/
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